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An object of mass "m" is at point A on a vertical circle of radius "R". If it is moved to B along ACB work done is

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2 π Rmg

2Rmg

π R^{2} mg

\frac{{mR}^{2}}{2}

answer is B.

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Detailed Solution

Work done in a moving object from A to B is

w = mgh

w = mg (2R)

$w = 2 mgR$

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