Q.

An object of mass ‘m’ initially at rest on a smooth horizontal plane starts moving under the action of force F = 2N. In the process of its linear motion, the angle  θ (as shown in figure) between the direction of force and horizontal varies as θ=kx  , where ‘k’ is a constant and ‘x’ is the distance covered by the object from its initial position. The expression of kinetic energy of the object will be E=nksinθ . The value of ‘n’ is ......

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Detailed Solution

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θ=kx

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W=KEfKEidw=FdxW=F1dx=Fcoskxdx=2k(sinkx)E=W=2ksinkx=2ksinθ

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