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Q.

An object of mass m is moving in a uniform circular motion in the xy plane. The circle has radius R and the object is moving around the circle with speed v. The motion is projected onto the x-axis where it appears as simple harmonic motion according to x(t)=Rcos(ωt+ϕ). Here ω is equal to 

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a

v/R

b

m2R

c

v/(R sin ωt)

d

R/v

answer is A.

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Detailed Solution

Angular frequency of SHM is equal to angular velocity of particle ω=v/R

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