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Q.

An object of mass m is tied to a string of length L and a variable horizontal force is applied on it which starts at zero and gradually increases until the string makes an angle θ with the vertical. Work done by the force F is

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a

mgL

b

mgL(1-sinθ)

c

mgL(1+cosθ)

d

mgL(1-cosθ)

answer is C.

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Detailed Solution

WF+Wg = Change in KE =0 WF=-Wg =-[-mg(L-Lcos θ)]= mgL (1 -cos θ)

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