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An object of mass $2.0 k g$ moves in uniform circular motion on a horizontal frictionless table. The radius of the circle is $0.75 m$ and the centripetal force is $10.0 N$

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The work done by this force when the object moves through one-half of a complete revolution is $0 J$ .

The average force exerted on the object in any time interval is constant $= 10 N$

The angular velocity of object is constant.

The velocity of object is constant.

answer is A, C.

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Detailed Solution

$(A) {\vec{F}}_{centripetal} ⊥ \vec{V}$

$(B) {\vec{F}}_{a v} = m {\vec{a}}_{a v} = m \frac{△ \vec{V}}{△ t} =$ different for different interval

$(C) \overset{}{ω} = \frac{V}{r} a n d \vec{ω} i s d i r e c t e d a l o n g t h e a x i s o f t h e c i r c u l a r p a t h .$ along axis

$(D)$ direction of velocity changes

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