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Q.

An object of specific gravity 2 is hung from a massless string. Tension in the string is T1. Now the object is immersed in water so that half of its volume is submerged. Tension in the string is T2. Then

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a

3T2=4T1

b

2T2=T1

c

4T2=3T1

d

T2=T1

answer is C.

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Detailed Solution

Question Image

T1=mg=Vρbodyg

Question Image

T2+B=mg

⇒  T2+V2ρwg=Vρbody g

⇒T2=Vgρbody1-ρw2ρbody

⇒T2=mg1-12σ=T11-12σ

⇒T2=T11-12×2=34T1

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