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Q.

An object undergoing simple harmonic motion takes 0.5s to travel from one point of zero velocity to the next such point. The angular frequency of the motion is.

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a

$3 π r a d / s$

b

$\frac{π}{2} r a d / s$

c

$π r a d / s$

d

$2 π r a d / s$

answer is B.

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Detailed Solution

The period $T = 2 \times 0.5 = 1 \sec$ angular velocity $ω = \frac{2 π}{T} = 2 π r a d / s$

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