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An object viewed from a near point distance of 25 cm, using microscopic lens with magnification’6’, gives an unresolved image. A resolved image is observed at infinite distance with a total magnification double the earlier using an eyepiece along with the given lens and tube of length 0.6m, if the focal length of the eyepiece is equal to_____ cm.

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answer is 25.

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Detailed Solution

In case of simple microscope , Magnification, $m = 1 + \frac{D}{f_{0}} o r, 6 = 1 + \frac{D}{f_{0}} \Rightarrow 5 = \frac{25}{f_{0}} ∴ f_{0} = 5 c m$

As total magnification double using an eyepiece along with the given lens i.e, case of compound microscope, Magnification, $m = \frac{l . D}{f_{0} . f_{e}}$ or, $12 = \frac{60 \times 25}{5. f_{e}} ∴ f_{e} = 25 c m$

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