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An object weighs $10 N$ in the air. When it is immersed in water, it displaces $0.2 kg$ of water. Taking $g = 10 m / s^{2} .$ The weight of the object in water is [[1]] N.

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Detailed Solution

An object weighs

10 N

in the air. When it is immersed in water, it displaces

0.2 kg

of water. Taking

g = 10 m / s^{2} .

The weight of the object in water is 8 N.
Given data and assumptions:
Mass of water displaced

= 0.2 kg

∴ Weight of water displaced

= 0.2 \times g

= 0.2 \times 10 N

= 2 N

Buoyant force acting on the body = Weight of water displaced

= 2 N

Weight of object in water = Weight of object in air - buoyant force
=

10 - 2 N

= 8 N

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