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An object with a mass 10 kg moves at a constant velocity of 10 m/sec. A constant force then acts for 4 second on the object and gives it a speed of 2 m/sec in opposite direction. The acceleration produced in it, is

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$0 .3 m / \sec^{2}$

$- 0 .3 m / \sec^{2}$

$- 3 m / \sec^{2}$

$3 m / \sec^{2}$

answer is B.

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Detailed Solution

$\bar{a} = \frac{\vec{v_{2}} - \vec{v_{1}}}{t} = \frac{(- 2) - (+ 10)}{4} = \frac{- 12}{4} = - 3 m / s^{2}$

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