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An oblique projectile is at same height ‘h’ after 2s and 8s of projection from a level ground. The value ‘h’ is $(g = 10 m s^{- 2})$

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80 m

100 m

20 m

50 m

answer is D.

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Detailed Solution

$\frac{2 u \sin θ}{g} = (2 + 8) \Rightarrow u \sin θ = 5 g$

$h = u \sin θ t - \frac{1}{2} g t^{2}$

$= 5 g \times 2 - \frac{1}{2} \times g \times 2^{2} = 8 g$

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