An observer, 1.5m tall is 28.5m away from a $30 m$ high tower, then the angle of elevation of the top of the tower from the eye of the observer is:

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45 °

60 °

30 °

50 °

answer is A.

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Detailed Solution

Given,
Height of an observer = 1.5m
Height of the tower = 30m
Distance between the tower and the observer = 28.5m
Consider the figure,
Question Image

Here, height of the tower is 30m which can be written as h+1,5.
The angle of elevation,

tan a = Difference of the height of tower and the man Distance between the man and the tower ⇒ tan a = 30 − 1.5 28.5 ⇒ tan a = 28.5 28.5 ⇒ tan a = 1 ⇒ a = 45 °

So, the angle of elevation of the top of tower from the eye of observer is

45 °

.
Therefore, option 1 is correct.

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