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Q.

An observer  2 m tall is  103 m away from a tower.  The angle of elevation from his eye to the top of the tower is  30°.  The height of the tower is

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a

2 m

b

12 m

c

5 m

d

15 m

answer is A.

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Detailed Solution

SR=PQ=2 m

PS=QR=103 m

In ΔPST, tan30°=TSPS

⇒13=TS103

∴TS=10 m

∴ The height of the tower is h=TS+SR

h=10+2

h=12 m

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