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Q.

An oil drop has $6.4 \times 10^{- 19} C$ charge. How many electrons does this oil drop has? (Report the answer to the nearest integer)

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answer is 4.

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Detailed Solution

$n o . o f e l e c t r o n s = \frac{t o t a l c h \arg e}{c h \arg e o f e l e c t r o n} = \frac{6.4 \times 10^{- 19} C}{1.6 \times 10^{- 19} C} = 4$

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An oil drop has 6.4×10−19C charge. How many electrons does this oil drop has? (Report the answer to the nearest integer)