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An old pendulum clock gains 8.64 seconds per day when the room temperature is 10°C and loses 17.24 seconds per day when the room temperature is 40°C. The clock will show correct time when the room temperature is

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0°C

50°C

30°C

20°C

answer is D.

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Detailed Solution

Loses (or) gain $= \frac{1}{2} \propto Δt \times 86, 400$
$\begin{array}{l} 8 .64 = \frac{1}{2} \propto (θ - 10) 86, 400 \to (1) \\ 17 .24 = \frac{1}{2} \propto (40 - θ) 86400 \to (2) \\ \frac{(1)}{(2)} \Rightarrow θ = 20^{\circ} C \end{array}$

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