An oleum sample has ${SO}_{3}$ and $H_{2} {SO}_{4}$ in 2 : 3 mass ratio. Select the correct statement(s).

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% labelling of sample is 118%

% labelling of sample is 109%

If 9 gm $H_{2} O$ is added to 200 gm of above sample new labelling would be 104.3 %

If 9 gm $H_{2} O$ is added to 200 gm of above sample new labelling would be 104.5 %

answer is A, D.

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Detailed Solution

100 g oleum contains

$40 g {SO}_{3}$ and $60 {gH}_{2} {SO}_{4}$

$∴ %$ labelling $= 109 %$

If 9 g $H_{2} O$ is added to 200 g or 4.5 g is added to 100 g.

$∴$ New label $= [100 + \frac{4.5}{104.5} \times 100] = 104.3$

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