An opaque cylindrical tank with an open top has a diameter of 3.00 m and is completely filled with water. When the setting sun reaches an angle $37^{0}$ above the horizon, sunlight ceases to illuminate any part of the bottom of the tank. How deep is tank in meter?

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answer is A.

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Detailed Solution

By Snell’s law

1 $\sin 53^{0} = μ \sin r$

$\begin{array}{l} \frac{4}{5} = \frac{4}{3} sinr \\ \frac{4}{5} = \frac{4}{3} sinr \\ r = 37^{0} \\ Now tanr = \frac{3}{h} = \tan 37^{0} \\ \frac{3}{h} = \frac{3}{4} \\ ∴ h = 4 m \end{array}$

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