An open amide of 10g is subjected to Kjeldahl method to estimate the nitrogen. Liberated ammonia is treated with $1 M & 200 m L$ of $H_{2} S O_{4}$ and the left acid is back titrated with 1.5 M, 200 mL $N a O H$ solution. Same quantity of compound when analyzed for carbon & hydrogen gave $63 % o f C & 11 % o f H$ .
[ Note:- After dividing by smallest fraction round off the final number of atoms to nearest whole number] .
Molar mass of the compound $= x (g r m / m o l e)$
Total no. of monomethyl primary amides which give optically active amines on reaction with $B r_{2} / N a O H = y$ ; then $x + y = ?$

Question

An open amide of 10g is subjected to Kjeldahl method to estimate the nitrogen. Liberated ammonia is treated with $1 M & 200 m L$ of $H_{2} S O_{4}$ and the left acid is back titrated with 1.5 M, 200 mL $N a O H$ solution. Same quantity of compound when analyzed for carbon & hydrogen gave $63 % o f C & 11 % o f H$ .
[ Note:- After dividing by smallest fraction round off the final number of atoms to nearest whole number] .
Molar mass of the compound $= x (g r m / m o l e)$
Total no. of monomethyl primary amides which give optically active amines on reaction with $B r_{2} / N a O H = y$ ; then $x + y = ?$

Infinity Learn · Accepted Answer

%N=1.410×100=14 %C=63 %H=11 %O=12 C→6312=5.25→5.250.75=7 H→111=11→110.75≈15 N→1414=1→10.75≈1 O→1216=0.73→0.750.75=1 M.F→C7H15ON Monomethyl primaryamides.

Start JEE / NEET / Foundation preparation at rupees 99/day !!

Detailed Solution

hear from our champions

Get Expert Academic Guidance – Connect with a Counselor Today!