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Q.

An open flask has Helium gas at 2atm and 327°C. The flask is heated to 527°C at the same pressure. Th fraction of original gas remaining in the flask is

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a

1/4

b

3/4

c

1/2

d

2/5

answer is A.

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Detailed Solution

detailed_solution_thumbnail

 P1V1  T1  =P2V2 T2       

But the flask can hold only V1​ volume of air,

Volume of air expelled=V13

Fraction of air expelled out= (V1 / 3 )/(4V1/3)

Fraction of air remaining in flask= 114=3/4

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