Q.

An open lift is moving upwards at a constant acceleration of 2 m/s2. When its speed is 10m/s, a ball is projected vertically upward at a speed of 20m/s w.r.t to ground. After how much time (in secs), the ball returns to lift ?  (g=10m/s2) (rounding off to nearest integer)

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answer is 2.

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Detailed Solution

With reference to life
u=10m/s,  a=102=12
T=2ua=2012=53=1.67
 

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