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An open rectangular cistern when measured from outside is 1.35 m long, 1.08 m broad and 90 cm deep. It is made up of iron, which is 2.5 cm thick. Find the capacity of the cistern and the volume of the iron used.

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2.13815 m

3

4.13815 m

3

3.13815 m

3

1.13815 m

3

answer is A.

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Detailed Solution

Given, the outer dimensions of cistern.
The cistern from outside is 1.35 m long, 1.08 m broad and 90 cm deep.
The volume of a cuboid is l

×

×

h.
Outer Volume

= 1.35

×

1.08 m

×

90 cm
We know 1m=100 cm.
So, 90 cm=0.9m.
Therefore volume is

⇒ 1.35

× 1.08

× 0.9

⇒ 1.3122

3

The thickness of the cistern is 2.5 cm that is 0.025 m.
So, the inner dimensions = (1.35 -0.025 -0.025) m, (1.08-0.025-0.025) m, (0.9-0.025-0.025) m

⇒

1.30 m, 1.03 m, 0.85 m.
Inner volume

= 1.30

× 1.03

× 0.85

⇒ 1.13815

3

The capacity of the cistern = the inner volume that is 1.13815 m

3

.
Therefore, the correct option is 1.

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