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An open smooth conical glass fixed on the ground in vertical position with smaller cross section at bottom. A small particle of mass m lies on the bottom surface touching circumference as shown in the figure. An impulse is given to the particle (along the circumference in the horizontal direction) so that it moves with velocity $V_{0} .$ Which of the following is/are correct for the rest of motion of the particle?

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As the particle moving up mechanical energy conservation can be done

Angular momentum of the particle can be conserved about an axis passing through the centre of bigger circle

During the motion of the particle vertical acceleration of the particle can be equal to zero but horizontal acceleration can never be equal to zero

minimum speed of the particle to just reach the top is $\sqrt{\frac{4 g h}{3}}$

answer is A, C.

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