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An opera glass (Gallilean telescope) measures 9 cm from the objective to the eyepiece. The focal length of the objective is 15 cm. Its magnifying power is

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2.5

$\frac{2}{5}$

$\frac{5}{3}$

0.4

answer is A.

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Detailed Solution

$f_{0} - f_{e} = 9 cm and f_{e} = f_{0} - 9 = 15 - 9 = 6 cm \Rightarrow m = \frac{f_{0}}{f_{e}} = \frac{15}{6} = 2 .5$

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