Q.

An optically active substance 'A' is decomposing into optically active substance 'B' and 'C' as :

Ak=103min-1 2B+CThe specific rotations of A, B and C are + 40°, + 10° and- 30° per mole, respectively. Initially 'A' and 'C' were present in 4 : 3 mole ratio. After what time (in min), the sample becomes optically inactive?

(Given :ln75=0.34,ln2013=0.43

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answer is 430.

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Detailed Solution

 t=0  Aa2B-+C3a/4

t=t ax 2x 3a4+x

(ax)×40+2x×103a4+x30=0

7a4=6x103×t=lnaa7a20103×t=ln2013t=430min

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