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An orbital electron in the ground state of hydrogen has an angular momentum $L_{1}$ and an orbital electron in the ground state of lithium (doubly ionised ) has an angular momentum $L_{2}$ .Then:

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$L_{1} = L_{2}$

$L_{1} = 3 L_{2}$

$L_{2} = 3 L_{1}$

$L_{2} = 9 L_{1}$

answer is A.

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Detailed Solution

Doubly ionised positively lithium ion is a hydrogen like atom. Hence,

$L = mvr = \frac{nh}{2 π} for both$

which depends only on the value of n. Also for both n =1.

Hence, $L_{1} = L_{2} = \frac{h}{2 π}$

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