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Q.

An ore is found to contain 23290 Th and it's stable end product is in atom ratio of 1 : 3 respectively. How many times the age of ore will be that of half life of 23290 Th?

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answer is 2.

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Detailed Solution

Here, we have,

t=1λln aax=T1/2ln 2ln 41t=2×T1/2

Thus, it is 2 times the half life.

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