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Q.

An organ pipe 40 cm long is open at both ends. The speed of sound in air is $360 m s^{- 1}$ . The frequency of the second harmonic is ________Hz.

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answer is 900.

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Detailed Solution

Open orgenpipe, second harmonic

$n = \frac{2 V}{2 l} = \frac{360}{40 \times 10^{- 2}} = 900 H z$

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