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Q.

An organ pipe 40cm long is open at both ends. The speed of sound in air is $360 m s^{- 1}$ . The frequency of the second harmonic is ----------Hz.

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answer is 900.

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Detailed Solution

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$f = \frac{V}{λ} = \frac{V}{L} = \frac{360}{\frac{40}{100}} = 900 H z$

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