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An organ pipe open on both ends in the nth harmonic is in resonance with a source of 1000 Hz. The length of pipe is 16.6 cm and speed of sound in air is 332 m/s. Find the value of n.

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answer is C.

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Detailed Solution

Given, $f = 1000 Hz, v = 332 m / s$

$l = 16.6 cm = 16.6 \times 10^{- 2} m$

Frequency in an organ pipe open on both ends,

$f = \frac{n v}{2 l} \Rightarrow n = \frac{2 f l}{v}$

or $n = \frac{2 \times 1000 \times 16.6 \times 10^{- 2}}{332} = 1$

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