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An organic base is tetraacidic. If from every 10 gm of the chloroplatinate salt of the base 3.9 gm of residue of platinum is obtained, then what will be the molecular mass of the base? [Pt= 195]

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180

360

270

answer is A.

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Detailed Solution

Chlosoplatinat salt $B_{2} (H_{2} {PtCl}_{6})$

$\underset{10 g}{B_{2}} {(H_{2} {PtCl}_{6})}_{4} \overset{Δ}{⟶} \underset{3.9 g}{Pt}$

$\frac{10 \times 4}{2 B + 410 \times 4} = \frac{3.9}{195}$

$\begin{array}{l} 40 \times 195 = 3.9 \times 2 B + 410 \times 4 \times 3.9 \\ ∴ B = \frac{40 \times 195 - 410 \times 4 \times 3.9}{7.8} \end{array}$

$\Rightarrow B = 180$

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