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An organic compound (A) (molecular formula $C_{6} H_{12} O_{2}$ ) was hydrolysed with dil. $H_{2} {SO}_{4}$ to give a carboxylic acid (B) and an alcohol (C). ‘C’ gives white turbidity immediately when treated with anhydrous ${ZnCl}_{2}$ and conc. HCl. The organic compound (A) is :

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answer is D.

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Detailed Solution

“C” is an alcohol which gives immediate turbidity with Lucas reagent so it must be 3°alcohol

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