An organic compound ‘A’ reacts with ‘Na’ metal to form a compound ‘B’ and evolves a gas which burns with pop sound. Compound ‘A’ on treatment with an alcohol ‘C’ in the presence of little conc. $H_{2} S O_{4}$ to form a sweet smelling compound ‘D’. What is the functional group present in compound ‘A’?

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Ester

Carboxylic acid

Alcohol

All

answer is C.

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Detailed Solution

Carboxylic acid.

$2 C H_{3} C O O H + 2 N a \to \underset{(B)}{2 C H_{3} C O O N a} + H_{2}$

$\underset{(A)}{C H_{3} C O O H} + \underset{(C)}{C_{2} H_{5} O H} \overset{H^{+}}{\to} \underset{D}{C H_{3} C O O C_{2} H_{5} + H_{2} O}$

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