An organic compound (A) with molecular formula $C_{11}{H}_{22}{O}_2$ on hydrolysis gives two optically active compound (B) and (C). Compound (C) is soluble in NaOH and compound (B), which gives negative iodoform test and on heating with conc. $H_{2}S{O}_4$  produces compound (D) with No diastereomers. When $\text{'}Ag\text{'}$ salt of compound (C) is treated with  $B{r}_2$, gives compound (E), which is also obtained when compound (B) is treated with $TsCl$ and then with $NaBr$.