An organic compound ‘A’ with the molecular formula C₄H₁₀O on oxidation with acidified K₂Cr₂O₇ gives compound ‘B’ with the formula C₃H₆O. Again ‘B’ on oxidation with acidified K₂Cr₂O₇ gives ‘C’ with the molecular formula C₂H₄O₂. IUPAC name of ‘A’ is

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1–Butanol

2–Methylbutanol–1

2–Butanol

2–Methyl–2–propanol

answer is C.

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Detailed Solution

$\underset{A}{{({CH}_{3})}_{3} C - OH} \overset{K_{2} {Cr}_{2} O_{7}}{\to} \underset{B}{{CH}_{3} - CO - {CH}_{3}} + HCOOH {CH}_{3} - CO - {CH}_{3} \overset{K_{2} {Cr}_{2} O_{7}}{\to} \underset{C}{{CH}_{3} - COOH} + HCOOH$

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