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Q.

An organic compound ‘A’ with the molecular formula C₄H₁₀O on oxidation with acidified K₂Cr₂O₇ gives compound ‘B’ with the formula C₃H₆O. Again ‘B’ on oxidation with acidified K₂Cr₂O₇ gives ‘C’ with the molecular formula C₂H₄O₂. IUPAC name of ‘A’ is

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a

1–Butanol

b

2–Methylbutanol–1

c

2–Butanol

d

2–Methyl–2–propanol

answer is C.

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Detailed Solution

$\underset{A}{{({CH}_{3})}_{3} C - OH} \overset{K_{2} {Cr}_{2} O_{7}}{\to} \underset{B}{{CH}_{3} - CO - {CH}_{3}} + HCOOH {CH}_{3} - CO - {CH}_{3} \overset{K_{2} {Cr}_{2} O_{7}}{\to} \underset{C}{{CH}_{3} - COOH} + HCOOH$

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An organic compound ‘A’ with the molecular formula C4H10O on oxidation with acidified K2Cr2O7 gives compound ‘B’ with the formula C3H6O. Again ‘B’ on oxidation with acidified K2Cr2O7 gives ‘C’ with the molecular formula C2H4O2. IUPAC name of ‘A’ is