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An organic compound containing ‘C’ and ‘H’ has 92.3% of carbon. What is its empirical formula ?

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CH₃

CH₄

CH₂

answer is D.

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Detailed Solution

Percentage atomic weight of C and H:

$C : H \frac{92.30}{12} : \frac{7.7}{1} 7.7 : 7.7 1 : 1$

In the above numerical expression, both C and H are in their simplest whole number ratio, hence option-D is correct.

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