An organic compound contains 20.0% C, 6.66% H, 47.33% N and the rest was oxygen. Its molar mass is $60 g {\mathrm{mol}}^{-1}$ The molecular formula of the compound is

Ratio of atoms $\mathrm{C}:\mathrm{H}:\mathrm{N}:\mathrm{O}::\frac{20.0}{12}:\frac{6.66}{1}:\frac{47.33}{14}:\frac{26.01}{16}::1.67:6.66:3.38:1.63::1:4:2:1$Empirical formula $={\mathrm{CH}}_4{\mathrm{N}}_2\mathrm{O}$

Molar empirical formula mass $=60\mathrm{g}{\mathrm{mol}}^{-1}$
Molecular formula $={\mathrm{CH}}_4{\mathrm{N}}_2\mathrm{O}$