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An organic compound contains 78% (by wt.) carbon and remaining percentage of hydrogen. The right option for the empirical formula of this compound is : [Atomic wt. of C is 12, H is 1]

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CH₄

CH₂

CH₃

answer is D.

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Detailed Solution

% C = 78
% H = 22
$C : H = \frac{78}{12} : \frac{22}{1}$
= 6.5 : 22
$\frac{6.5}{6.5} : \frac{22}{6.5} = 1 : 3.3$
C : H = CH₃

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