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Q.

An organic compound  CxH2yOy was burnt with twice the amount of  O2 gas as required for complete combustion into  CO2  and  H2O. The hot gases when cooled to 00C and 1 atm pressure measured 2.24 litres. The water collected during the cooling weighs 0.9 grams. The vapour pressure of pure water is 17.5 mm of Hg at 200C and is lowered by 0.104 mm of Hg when 50 grams of organic compound is dissolved in 1000 grams water.(Assume that organic compound is non volatile and does not dissociate or associate). The molecular formula of the compound is

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a

C5H5O10

b

C5H10O10

c

C10H10O5

d

C5H10O5

answer is A.

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Detailed Solution

CxH2yOy+2xO2xCO2+yH2O+xO2

Number of moles after cooling =2x
Volume after cooling=2.24 litres
Number moles of CO2 =0.05

EF= CH2O

P0=17.5mm

P0P=0.104mm

M=151.4
MF= C5H10O5

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