An organic compound gives 0.220 g of CO₂ and 0.126g of H₂O on complete combustion. If the % of carbon is 24 then the % of hydrogen is _________ $\times {\text{10}}^{-1}.$(Nearest integer)

$$\begin{gathered} 44\mathrm{g}\mathrm{of}{{\mathrm{CO}}_2}^{\_\_\_\_}12\mathrm{g}\mathrm{of}\mathrm{C} \\ 0.22\mathrm{g}\text{\hspace{0.17em}of\hspace{0.17em}}{{\mathrm{CO}}_2}^{\_\_\_\_}?=0.06\mathrm{g}\text{\hspace{0.17em}of\hspace{0.17em}}\mathrm{C} \end{gathered}$$
$24=\frac{0.06}{\mathrm{x}}\times 100 \mathrm{x}=\text{weight\hspace{0.17em}of\hspace{0.17em}compound\hspace{0.17em}}=0.25\mathrm{g}$
$$\begin{gathered} 18\mathrm{g}\text{\hspace{0.17em}of\hspace{0.17em}}{\mathrm{H}}_2{\mathrm{O}}^{\_\_\_\_}2\mathrm{g}\text{\hspace{0.17em}of\hspace{0.17em}}\mathrm{H} \\ 0.126\mathrm{g}\text{\hspace{0.17em}of\hspace{0.17em}}{\mathrm{H}}_2{\mathrm{O}}^{\_\_\_\_}?=0.014\mathrm{g}\text{\hspace{0.17em}of\hspace{0.17em}}\mathrm{H} \end{gathered}$$
$\mathrm{\%}\mathrm{H}=\frac{0.014}{0.25}\times 100=5.6\mathrm{\%}=56\times {10}^{-1}$