An organic compound gives 0.220 g of CO2 and 0.126g of H2O on complete combustion. If the % of carbon is 24 then the % of hydrogen is _________ ×10−1.(Nearest integer)

44g of CO2____12g of C 0.22g of CO2____? =0.06g of C24=0.06x×100 x=weight of compound = 0.25 g18g of H2O____2g of H 0.126g of H2O____? =0.014g of H%H=0.0140.25 ×100=5.6%=56×10−1

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An organic compound gives 0.220 g of CO₂ and 0.126g of H₂O on complete combustion. If the % of carbon is 24 then the % of hydrogen is _________ $\times 10^{- 1} .$ (Nearest integer)

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answer is 56.

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Detailed Solution

$44 g of {CO}_{2}^{____} 12 g of C 0.22 g of {CO}_{2}^{____} ? = 0.06 g of C$
$24 = \frac{0.06}{x} \times 100 x = weight of compound = 0.25 g$
$18 g of H_{2} O^{____} 2 g of H 0.126 g of H_{2} O^{____} ? = 0.014 g of H$
$% H = \frac{0.014}{0.25} \times 100 = 5.6 % = 56 \times 10^{- 1}$