An organic compound is found to contain 30.04% by mass of sulphur. When such a compound is
heated in Carius tube with sutable reagents, 0.1 × gm. Of ${BaSO}_{4} [MW = 233]$ is formed from 0.32
gm of the compound. The value of x _____

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answer is B.

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Detailed Solution

$%S = \frac{32 × weight of Bases × 100}{233 × Weight of O.C}$

$30.04 = \frac{32 \times 0.1 \times x 100}{233 \times 0.32}$

$30.04 = \frac{1000 x}{233} x = \frac{30.04 \times 233}{1000}$

$x = 6.99$

$x = 7$

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