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Q.

An organic compound is found to contain C=54.5%, O=36.4% and H=9.1% by mass. Its empirical formula is

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a

 C2 H4 O

b

 CHO2

c

 C3 H4 O

d

 CH2 O

answer is C.

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Detailed Solution

 Let compound be 100 g.

ElementCOH
Mass54.536.49.1
No. of atoms54.5/12=4.5436.4/16=2.279.1/1=9.1
Relative no. of atoms4.54/2.27=22.27/2.27=19.1/2.27=4

Hence the empirical formula is C2 H4 O.

Hence option C is the correct answer.

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