An organic compound on analysis gave C = 48 g, H : 8 g and N : 56 g. Volume of 1.0 g of the compound was found to be 200 ml at NTP. Molecular formula of the compound is

$\mathrm{Empirical} \mathrm{formula} = {\mathrm{CH}}_2\mathrm{N}$

Empirical formula mass = 28
Now, 200 ml of compound = 1 g

$$\begin{gathered} 22400 \mathrm{ml} \mathrm{of} \mathrm{compound} \frac{1}{200} \times 22400 = 112\mathrm{g} ; \\ \mathrm{n} = \frac{\mathrm{Mol}. \mathrm{of} \mathrm{mass}}{\mathrm{Emp}. \mathrm{formula} \mathrm{mass} } = \frac{112}{28}=4 \\ \mathrm{Therefore}, \mathrm{Molecular} \mathrm{formula} = {\left({\mathrm{CH}}_2\mathrm{N}\right)}_4 = {\mathrm{C}}_4{\mathrm{H}}_8{\mathrm{N}}_4. \end{gathered}$$