An organic compound on reaction with $O_{3}$ followed by Zn and $H_{2} O$ gives ${CH}_{3} {COCH}_{2} {CH}_{2} {COCH}_{3}$ . How many of the following compounds can gives this product

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answer is 3.

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Detailed Solution

a) ${CH}_{2} \frac{3}{3} C - {CH}_{2} - {CH}_{2} - C \frac{3}{3} {CH}_{2} \frac{(i) O_{3}}{\frac{(i i) \geq n / H_{2} O}{⟶}} 2 H - C - H + {CH}_{3} - C - {CH}_{2} - {CH}_{2} - C - {CH}_{3}$ b) Question Image

c) Question Image

d) will give glyoxal and dimethyl glyoxal.

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