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Q.

An orifice of area 10 sq mm is made at the bottom of vessel containing water to a height of 10 m above the orifice. What is the force on the vessel in N $(g = 10 m / s^{2})$

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answer is 2.

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Detailed Solution

$V = \sqrt{2 gh} = \sqrt{2 \times 10 \times 10}$

$F = {ρaV}^{2} = 10^{3} \times 10 \times 10^{- 6} \times 2 \times 10 \times 10 = 2 N$

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