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An oxide of a metal (M) contains 40% by mass of oxygen and metal (M) has atomic mass of 24. The empirical formula of the oxide is ____?

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$M_{2} O_{3}$

$M_{3} O_{4}$

$M_{2} O$

answer is B.

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Detailed Solution

$\begin{array}{l} M = \frac{60}{24} = 2.5 \\ O = \frac{40}{16} = 2.5 \end{array}$

Simplest ratio $= 1 : 1$

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