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Q.

An oxide of nitrogen has a molecular weight 92. Find the total number of electrons in one gram mole of that oxide.

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a

$4.6 N_{A}$

b

46 $N_{A}$

c

$23 N_{A}$

d

$2.3 N_{A}$

answer is B.

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Detailed Solution

Nitrogen oxide $N_{2} O_{4} has moleular weight = \underset{(28 + 64)}{N_{2} O_{4}} = 92$

1 molecule $N_{2} O_{4} = 14 + 32 = 46 e^{-}$

1 mole $N_{2} O_{4} = 46 N e^{-}$

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