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Q.

An oxide which gives H₂O₂ on treatment with dilute acid is

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a

PbO₂

b

Na₂O₂

c

MnO₂

d

TiO₂

answer is B.

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Detailed Solution

${Na}_{2} O_{2} + 2 HCl \overset{}{\to} 2 NaCl + H_{2} O_{2} {Na}_{2} O_{2} + H_{2} {SO}_{4} \overset{}{\to} {Na}_{2} {SO}_{4} + H_{2} O_{2}$

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