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Q.

An α-particle of energy 4 MeV is scattered by gold foil (Z=79). Calculate the maximum volume in which positive charge of the atom is likely to be concentrated.

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a

5.5 x 10–40 m3

b

3.3 x 10–40 m3

c

11 x 10–40 m3

d

7.7 x 10–40 m3

answer is B.

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Detailed Solution

E=14πϵ0⋅2Ze2r04×106×1.6×10−19=9×109×2(79)1.6×10−192r0∴r0=5.7×10−14m→(1)→V=43πr03=4×3.1435.7×10−143=7.7×10−40

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