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An unbiased coin is tossed to get 2 points for turning up a head and one point for the tail. If three unbiased coins are tossed simultaneously, then the probability of getting a total of odd number of points is

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\frac{1}{2}

\frac{1}{4}

\frac{1}{8}

\frac{3}{8}

answer is A.

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Detailed Solution

n (E) =

To get sum as odd possibilities are

Question Image

$n (S) = 2^{3} = 8$

$∴ P (E) = \frac{n (E)}{n (S)} = \frac{4}{8} = \frac{1}{2}$

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