An underwater swimmer is at a depth of 12 m below the surface of water. A bird is at a height of 18 m from the surface of water. Directly above his eyes. For the swimmer the bird appears to be at a distance equal to (Refractive index of water is 4/3)

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18 m

9 m

36 m

24 m

answer is A.

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Detailed Solution

Here, the bird lies in Air medium and observer is the swimmer which lies in water.

Refractive index= real depth/apparent depth $\frac{4}{3} = \frac{real depth}{18}$

Real depth $\frac{4}{3} \times 18 = 24 m$

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